golang math/rand 내의 Int() 호출하여 처리하기

간단하게 3 * 3  에 맞는 것을 배열에 표시하기.

총 9개를 각각 랜덤 모듈을 이용해서 간단하게 배열내에 있는 값으로 배치하기

package main

import (

"fmt"

"math/rand"

)

func main() {

fmt.Println(" random test ")

var a Cube

a.Set(1)

fmt.Println(" level", a.Level)

fmt.Println(" list ", a.List)

a.Set(2)

fmt.Println(" level 2 ", a.Level)

fmt.Println(" list 2 ", a.List)

a.Set(3)

fmt.Println(" level", a.Level)

fmt.Println(" list ", a.List)

}

var Pocket [24]int = [24]int{10, 10, 10, 10,

21, 22, 23, 24,

31, 32, 33, 34,

41, 42, 43, 44,

51, 52, 53, 54,

60, 60, 60, 60}

var Pocket1 [18]int = [18]int{10,

21, 22, 23, 24,

31, 32, 33, 34,

41, 42, 43, 44,

51, 52, 53, 54,

60}

var levelAr [3]int = [3]int{100, 10000, 1000000}

var pocket [3]int = [3]int{24, 18, 18}

type Cube struct {

Level int

List  [9]int

}

func (this *Cube) Set(level int) {

this.Level = level

levelCalc(this, level)

}

func levelCalc(this *Cube, level int) {

for i := 0; i < 9; i++ {

any := 0

v := rand.Int()

s := v / levelAr[level-1]

t := v - (s * levelAr[level-1])

fmt.Println(" t ", t)

if t > pocket[level-1] {

any = t % pocket[level-1]

} else {

any = t

}

switch level {

case 1:

this.List[i] = Pocket[any]

case 2:

this.List[i] = Pocket1[any]

case 3:

this.List[i] = Pocket1[any]

}

}

}